A matching in a graph G is a subset M of the edges of G such that no two share an endpoint.
An odd-set cover OSC of G is a labeling of the nodes of G with non-negative integers such that every edge of G (which is not a self-loop) is either incident to a node labeled 1 or connects two nodes labeled with the same i, i > = 2.
Let ni be the number of nodes labeled i and consider any matching N. For i, i > = 2, let Ni be the edges in N that connect two nodes labeled i. Let N1 be the remaining edges in N. Then | Ni| < = ni/2 and | N1| < = n1 and hence
It can be shown that for a maximum cardinality matching M there is always an odd-set cover OSC with
list<edge> | MAX_CARD_MATCHING_EDMONDS(const graph& G, node_array<int>& OSC, int heur=1) | |
computes a maximum cardinality matching M in a general graph G and returns it as a list of edges. The original algorithm was developed by Edmond in [27]. An efficient implementation was presented by Gabow and Edmond in [39]. It has running time O(nm*(n, m)). With heur = 1 the algorithm uses a greedy heuristic to find an initial matching. An odd-set cover that proves the maximality of M is returned in OSC. | ||
list<edge> | MAX_CARD_MATCHING_KECECIOGLU(const graph& G, node_array<int>& OSC, int heur=1) | |
a variant of Gabow/Edmond's algorithm using an heuristic proposed by J. Kececioglu and J. Pecquer. | ||
list<edge> | MAX_CARD_MATCHING_GABOW(const graph& G, node_array<int>& OSC) | |
a new algorithm by Gabow ([40]) with running time O(*m). The implementation was done by Ansaripour,Danaei and Mehlhorn ([2]). | ||
bool | CHECK_MAX_CARD_MATCHING(const graph& G, const list<edge>& M, const node_array<int>& OSC) | |
checks whether M is a maximum cardinality matching in G and OSC is a proof of optimality. Aborts if this is not the case. | ||
list<edge> | MAX_CARD_MATCHING(const graph& G, node_array<int>& OSC, int heur = 1) | |
computes a maximum cardinality matching in a general G and an odd-set cover OSC by calling MAX_CARD_MATCHING_GABOW. | ||
list<edge> | MAX_CARD_MATCHING(const graph& G, int heur = 0) | |
as above, but no proof of optimality is returned. |